$$\frac{ 7 }{ 9 } + \frac{ 2 }{ 4 } - \frac{ 3 }{ 5 } \times \frac{ 2 }{ 8 } +( \frac{ 4 }{ 3 } - \frac{ 2 }{ 1 } )$$
$\frac{83}{180}\approx 0.461111111$
$$\frac{7}{9}+\frac{1}{2}-\frac{3}{5}\times \frac{2}{8}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{14}{18}+\frac{9}{18}-\frac{3}{5}\times \frac{2}{8}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{14+9}{18}-\frac{3}{5}\times \frac{2}{8}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{23}{18}-\frac{3}{5}\times \frac{2}{8}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{23}{18}-\frac{3}{5}\times \frac{1}{4}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{23}{18}-\frac{3\times 1}{5\times 4}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{23}{18}-\frac{3}{20}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{230}{180}-\frac{27}{180}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{230-27}{180}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{203}{180}+\frac{4}{3}-\frac{2}{1}$$
$$\frac{203}{180}+\frac{240}{180}-\frac{2}{1}$$
$$\frac{203+240}{180}-\frac{2}{1}$$
$$\frac{443}{180}-\frac{2}{1}$$
$$\frac{443}{180}-2$$
$$\frac{443}{180}-\frac{360}{180}$$
$$\frac{443-360}{180}$$
$$\frac{83}{180}$$
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$\frac{83}{2 ^ {2} \cdot 3 ^ {2} \cdot 5} = 0.46111111111111114$