How to solve 7/9 + 4/5 * 4/9 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/9 + 4/5 * 4/9 = | Equatix

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$$\frac{7}{9}+\frac{4}{5}\times\frac{4}{9}=$$

$\frac{17}{15}\approx 1.133333333$

Multiply $\frac{4}{5}$ times $\frac{4}{9}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{9}+\frac{4\times 4}{5\times 9}$$

Do the multiplications in the fraction $\frac{4\times 4}{5\times 9}$.

$$\frac{7}{9}+\frac{16}{45}$$

Least common multiple of $9$ and $45$ is $45$. Convert $\frac{7}{9}$ and $\frac{16}{45}$ to fractions with denominator $45$.

$$\frac{35}{45}+\frac{16}{45}$$

Since $\frac{35}{45}$ and $\frac{16}{45}$ have the same denominator, add them by adding their numerators.

$$\frac{35+16}{45}$$

Add $35$ and $16$ to get $51$.

$$\frac{51}{45}$$

Reduce the fraction $\frac{51}{45}$ to lowest terms by extracting and canceling out $3$.

$$\frac{17}{15}$$

$\frac{17}{3 \cdot 5} = 1\frac{2}{15} = 1.1333333333333333$