How to solve 7/- 15 + (4/- 3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/- 15 + (4/- 3) | Equatix

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$$\frac{7}{-15}+(\frac{4}{-3})$$

$-\frac{9}{5}=-1.8$

Fraction $\frac{7}{-15}$ can be rewritten as $-\frac{7}{15}$ by extracting the negative sign.

$$-\frac{7}{15}+\frac{4}{-3}$$

Fraction $\frac{4}{-3}$ can be rewritten as $-\frac{4}{3}$ by extracting the negative sign.

$$-\frac{7}{15}-\frac{4}{3}$$

Least common multiple of $15$ and $3$ is $15$. Convert $-\frac{7}{15}$ and $\frac{4}{3}$ to fractions with denominator $15$.

$$-\frac{7}{15}-\frac{20}{15}$$

Since $-\frac{7}{15}$ and $\frac{20}{15}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-7-20}{15}$$

Subtract $20$ from $-7$ to get $-27$.

$$\frac{-27}{15}$$

Reduce the fraction $\frac{-27}{15}$ to lowest terms by extracting and canceling out $3$.

$$-\frac{9}{5}$$

$-\frac{9}{5} = -1\frac{4}{5} = -1.8$