How to solve 7 -26 + 16 39 ]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7 -26 + 16 39 ] | Equatix

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$$\frac{7}{-26}+\frac{16}{39}]$$

$\frac{11}{78}\approx 0.141025641$

Fraction $\frac{7}{-26}$ can be rewritten as $-\frac{7}{26}$ by extracting the negative sign.

$$-\frac{7}{26}+\frac{16}{39}$$

Least common multiple of $26$ and $39$ is $78$. Convert $-\frac{7}{26}$ and $\frac{16}{39}$ to fractions with denominator $78$.

$$-\frac{21}{78}+\frac{32}{78}$$

Since $-\frac{21}{78}$ and $\frac{32}{78}$ have the same denominator, add them by adding their numerators.

$$\frac{-21+32}{78}$$

Add $-21$ and $32$ to get $11$.

$$\frac{11}{78}$$

$\frac{11}{2 \cdot 3 \cdot 13} = 0.14102564102564102$