How to solve (7-3x)/(2) < x+1

Q: How to solve (7-3x)/(2) < x+1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (7-3x)/(2) < x+1 | Equatix

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3(r+2s)=2t-4

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Question

$$\frac{ 7-3x }{ 2 } < x+1$$

Solve for x

$x>1$

Solution Steps

Multiply both sides of the equation by $2$. Since $2$ is positive, the inequality direction remains the same.

$$7-3x<2x+2$$

Subtract $2x$ from both sides.

$$7-3x-2x<2$$

Combine $-3x$ and $-2x$ to get $-5x$.

$$7-5x<2$$

Subtract $7$ from both sides.

$$-5x<2-7$$

Subtract $7$ from $2$ to get $-5$.

$$-5x<-5$$

Divide both sides by $-5$. Since $-5$ is negative, the inequality direction is changed.

$$x>\frac{-5}{-5}$$

Divide $-5$ by $-5$ to get $1$.

$$x>1$$

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