Question

$$\frac{7-4\sqrt{60}}{3\sqrt{20-5\sqrt{12}}$$

Answer

$$7-48240*sq*r^2*t^2*s*q-60*sq*r*t$$

Solution


Take out the constants.
\[7-(4\times 603\times 20)rrttsqsq-5sqrt\times 12\]
Simplify  \(4\times 603\)  to  \(2412\).
\[7-(2412\times 20)rrttsqsq-5sqrt\times 12\]
Simplify  \(2412\times 20\)  to  \(48240\).
\[7-48240rrttsqsq-5sqrt\times 12\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[7-48240{r}^{2}{t}^{2}sqsq-5sqrt\times 12\]
Regroup terms.
\[7-48240sq{r}^{2}{t}^{2}sq-5sqrt\times 12\]
Simplify  \(5sqrt\times 12\)  to  \(60rtsq\).
\[7-48240sq{r}^{2}{t}^{2}sq-60rtsq\]
Regroup terms.
\[7-48240sq{r}^{2}{t}^{2}sq-60sqrt\]