How to solve 72/3 + 63/6 + 3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 72/3 + 63/6 + 3 | Equatix

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Question

$$\frac{72}{3}+\frac{63}{6}+3$$

Evaluate

$\frac{75}{2}=37.5$

Solution Steps

Divide $72$ by $3$ to get $24$.

$$24+\frac{63}{6}+3$$

Reduce the fraction $\frac{63}{6}$ to lowest terms by extracting and canceling out $3$.

$$24+\frac{21}{2}+3$$

Convert $24$ to fraction $\frac{48}{2}$.

$$\frac{48}{2}+\frac{21}{2}+3$$

Since $\frac{48}{2}$ and $\frac{21}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{48+21}{2}+3$$

Add $48$ and $21$ to get $69$.

$$\frac{69}{2}+3$$

Convert $3$ to fraction $\frac{6}{2}$.

$$\frac{69}{2}+\frac{6}{2}$$

Since $\frac{69}{2}$ and $\frac{6}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{69+6}{2}$$

Add $69$ and $6$ to get $75$.

$$\frac{75}{2}$$

Show Solution

Factor

$\frac{3 \cdot 5 ^ {2}}{2} = 37\frac{1}{2} = 37.5$