How to solve (7x)/9 + 1/2 = 8x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (7x)/9 + 1/2 = 8x | Equatix

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$$\frac{7x}{9}+\frac{1}{2}=8x$$

$x=\frac{9}{130}\approx 0.069230769$

Multiply both sides of the equation by $18$, the least common multiple of $9,2$.

$$2\times 7x+9=144x$$

Multiply $2$ and $7$ to get $14$.

$$14x+9=144x$$

Subtract $144x$ from both sides.

$$14x+9-144x=0$$

Combine $14x$ and $-144x$ to get $-130x$.

$$-130x+9=0$$

Subtract $9$ from both sides. Anything subtracted from zero gives its negation.

$$-130x=-9$$

Divide both sides by $-130$.

$$x=\frac{-9}{-130}$$

Fraction $\frac{-9}{-130}$ can be simplified to $\frac{9}{130}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{9}{130}$$