$$\frac{7y-2}{5y-1}=\frac{3+7y}{4+5y}$$
$y=\frac{1}{2}=0.5$
$$\left(5y+4\right)\left(7y-2\right)=\left(5y-1\right)\left(3+7y\right)$$
$$35y^{2}+18y-8=\left(5y-1\right)\left(3+7y\right)$$
$$35y^{2}+18y-8=8y+35y^{2}-3$$
$$35y^{2}+18y-8-8y=35y^{2}-3$$
$$35y^{2}+10y-8=35y^{2}-3$$
$$35y^{2}+10y-8-35y^{2}=-3$$
$$10y-8=-3$$
$$10y=-3+8$$
$$10y=5$$
$$y=\frac{5}{10}$$
$$y=\frac{1}{2}$$
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