Question

$$\frac{ 8 { y }^{ 3 } -2y }{ y }$$

Answer

2*(2*y+1)*(2*y-1)

Solution


Factor out the common term \(2y\).
\[\frac{2y(4{y}^{2}-1)}{y}\]
Rewrite \(4{y}^{2}-1\) in the form \({a}^{2}-{b}^{2}\), where \(a=2y\) and \(b=1\).
\[\frac{2y({(2y)}^{2}-{1}^{2})}{y}\]
Use Difference of Squares: \({a}^{2}-{b}^{2}=(a+b)(a-b)\).
\[\frac{2y(2y+1)(2y-1)}{y}\]
Cancel \(y\).
\[2(2y+1)(2y-1)\]