How to solve 8/10 = (6x)/4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8/10 = (6x)/4 | Equatix

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$$\frac{8}{10}=\frac{6x}{4}$$

$x=\frac{8}{15}\approx 0.533333333$

Multiply both sides of the equation by $20$, the least common multiple of $10,4$.

$$2\times 8=5\times 6x$$

Multiply $2$ and $8$ to get $16$.

$$16=5\times 6x$$

Multiply $5$ and $6$ to get $30$.

$$16=30x$$

Swap sides so that all variable terms are on the left hand side.

$$30x=16$$

Divide both sides by $30$.

$$x=\frac{16}{30}$$

Reduce the fraction $\frac{16}{30}$ to lowest terms by extracting and canceling out $2$.

$$x=\frac{8}{15}$$