How to solve 8/12 + 4/9 + 3/7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8/12 + 4/9 + 3/7 | Equatix

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Question

$$\frac{8}{12}+\frac{4}{9}+\frac{3}{7}$$

Evaluate

$\frac{97}{63}\approx 1.53968254$

Solution Steps

Reduce the fraction $\frac{8}{12}$ to lowest terms by extracting and canceling out $4$.

$$\frac{2}{3}+\frac{4}{9}+\frac{3}{7}$$

Least common multiple of $3$ and $9$ is $9$. Convert $\frac{2}{3}$ and $\frac{4}{9}$ to fractions with denominator $9$.

$$\frac{6}{9}+\frac{4}{9}+\frac{3}{7}$$

Since $\frac{6}{9}$ and $\frac{4}{9}$ have the same denominator, add them by adding their numerators.

$$\frac{6+4}{9}+\frac{3}{7}$$

Add $6$ and $4$ to get $10$.

$$\frac{10}{9}+\frac{3}{7}$$

Least common multiple of $9$ and $7$ is $63$. Convert $\frac{10}{9}$ and $\frac{3}{7}$ to fractions with denominator $63$.

$$\frac{70}{63}+\frac{27}{63}$$

Since $\frac{70}{63}$ and $\frac{27}{63}$ have the same denominator, add them by adding their numerators.

$$\frac{70+27}{63}$$

Add $70$ and $27$ to get $97$.

$$\frac{97}{63}$$

Show Solution

Factor

$\frac{97}{3 ^ {2} \cdot 7} = 1\frac{34}{63} = 1.5396825396825398$