How to solve 8/15 - 4/12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8/15 - 4/12 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$\frac{8}{15}-\frac{4}{12}$$

$\frac{1}{5}=0.2$

Reduce the fraction $\frac{4}{12}$ to lowest terms by extracting and canceling out $4$.

$$\frac{8}{15}-\frac{1}{3}$$

Least common multiple of $15$ and $3$ is $15$. Convert $\frac{8}{15}$ and $\frac{1}{3}$ to fractions with denominator $15$.

$$\frac{8}{15}-\frac{5}{15}$$

Since $\frac{8}{15}$ and $\frac{5}{15}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-5}{15}$$

Subtract $5$ from $8$ to get $3$.

$$\frac{3}{15}$$

Reduce the fraction $\frac{3}{15}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{5}$$

$\frac{1}{5} = 0.2$