How to solve 8/(2x - 3) = 4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8/(2x - 3) = 4 | Equatix

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$$\frac{8}{2x-3}=4$$

$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$

Variable $x$ cannot be equal to $\frac{3}{2}$ since division by zero is not defined. Multiply both sides of the equation by $2x-3$.

$$8=4\left(2x-3\right)$$

Use the distributive property to multiply $4$ by $2x-3$.

$$8=8x-12$$

Swap sides so that all variable terms are on the left hand side.

$$8x-12=8$$

Add $12$ to both sides.

$$8x=8+12$$

Add $8$ and $12$ to get $20$.

$$8x=20$$

Divide both sides by $8$.

$$x=\frac{20}{8}$$

Reduce the fraction $\frac{20}{8}$ to lowest terms by extracting and canceling out $4$.

$$x=\frac{5}{2}$$