How to solve 8/3 + 6/4 + 3/7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8/3 + 6/4 + 3/7 | Equatix

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Question

$$\frac{8}{3}+\frac{6}{4}+\frac{3}{7}$$

Evaluate

$\frac{193}{42}\approx 4.595238095$

Solution Steps

Reduce the fraction $\frac{6}{4}$ to lowest terms by extracting and canceling out $2$.

$$\frac{8}{3}+\frac{3}{2}+\frac{3}{7}$$

Least common multiple of $3$ and $2$ is $6$. Convert $\frac{8}{3}$ and $\frac{3}{2}$ to fractions with denominator $6$.

$$\frac{16}{6}+\frac{9}{6}+\frac{3}{7}$$

Since $\frac{16}{6}$ and $\frac{9}{6}$ have the same denominator, add them by adding their numerators.

$$\frac{16+9}{6}+\frac{3}{7}$$

Add $16$ and $9$ to get $25$.

$$\frac{25}{6}+\frac{3}{7}$$

Least common multiple of $6$ and $7$ is $42$. Convert $\frac{25}{6}$ and $\frac{3}{7}$ to fractions with denominator $42$.

$$\frac{175}{42}+\frac{18}{42}$$

Since $\frac{175}{42}$ and $\frac{18}{42}$ have the same denominator, add them by adding their numerators.

$$\frac{175+18}{42}$$

Add $175$ and $18$ to get $193$.

$$\frac{193}{42}$$

Show Solution

Factor

$\frac{193}{2 \cdot 3 \cdot 7} = 4\frac{25}{42} = 4.595238095238095$