How to solve 8/4 * 3/15 - 4/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8/4 * 3/15 - 4/9 | Equatix

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$$\frac{8}{4}\times\frac{3}{15}-\frac{4}{9}$$

$-\frac{2}{45}\approx -0.044444444$

Divide $8$ by $4$ to get $2$.

$$2\times \frac{3}{15}-\frac{4}{9}$$

Reduce the fraction $\frac{3}{15}$ to lowest terms by extracting and canceling out $3$.

$$2\times \frac{1}{5}-\frac{4}{9}$$

Multiply $2$ and $\frac{1}{5}$ to get $\frac{2}{5}$.

$$\frac{2}{5}-\frac{4}{9}$$

Least common multiple of $5$ and $9$ is $45$. Convert $\frac{2}{5}$ and $\frac{4}{9}$ to fractions with denominator $45$.

$$\frac{18}{45}-\frac{20}{45}$$

Since $\frac{18}{45}$ and $\frac{20}{45}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{18-20}{45}$$

Subtract $20$ from $18$ to get $-2$.

$$-\frac{2}{45}$$

$-\frac{2}{45} = -0.044444444444444446$