How to solve 8/9 / (4/3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8/9 / (4/3) | Equatix

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$$\frac{8}{9}\div\frac{4}{3}$$

$\frac{2}{3}\approx 0.666666667$

Divide $\frac{8}{9}$ by $\frac{4}{3}$ by multiplying $\frac{8}{9}$ by the reciprocal of $\frac{4}{3}$.

$$\frac{8}{9}\times \frac{3}{4}$$

Multiply $\frac{8}{9}$ times $\frac{3}{4}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 3}{9\times 4}$$

Do the multiplications in the fraction $\frac{8\times 3}{9\times 4}$.

$$\frac{24}{36}$$

Reduce the fraction $\frac{24}{36}$ to lowest terms by extracting and canceling out $12$.

$$\frac{2}{3}$$

$\frac{2}{3} = 0.6666666666666666$