Since \(5\times 5=25\), the square root of \(25\) is \(5\).
\[\begin{aligned}&theof\times \frac{5}{3\sqrt{64}}+{(\frac{256}{625})}^{-\frac{1}{4}}\\&{(\frac{64}{125})}^{3}\\&\frac{1}{{(\frac{64}{125})}^{\frac{2}{2}}}\end{aligned}\]
Since \(8\times 8=64\), the square root of \(64\) is \(8\).
\[\begin{aligned}&theof\times \frac{5}{3\times 8}+{(\frac{256}{625})}^{-\frac{1}{4}}\\&{(\frac{64}{125})}^{3}\\&\frac{1}{{(\frac{64}{125})}^{\frac{2}{2}}}\end{aligned}\]
Simplify \(3\times 8\) to \(24\).
\[\begin{aligned}&theof\times \frac{5}{24}+{(\frac{256}{625})}^{-\frac{1}{4}}\\&{(\frac{64}{125})}^{3}\\&\frac{1}{{(\frac{64}{125})}^{\frac{2}{2}}}\end{aligned}\]
Cancel \(2\).
\[\begin{aligned}&theof\times \frac{5}{24}+{(\frac{256}{625})}^{-\frac{1}{4}}\\&{(\frac{64}{125})}^{3}\\&\frac{1}{{(\frac{64}{125})}^{1}}\end{aligned}\]
Use Rule of One: \({x}^{1}=x\).
\[\begin{aligned}&theof\times \frac{5}{24}+{(\frac{256}{625})}^{-\frac{1}{4}}\\&{(\frac{64}{125})}^{3}\\&\frac{1}{\frac{64}{125}}\end{aligned}\]
Simplify \(theof\times \frac{5}{24}\) to \(\frac{theof\times 5}{24}\).
\[\begin{aligned}&\frac{theof\times 5}{24}+{(\frac{256}{625})}^{-\frac{1}{4}}\\&{(\frac{64}{125})}^{3}\\&\frac{1}{\frac{64}{125}}\end{aligned}\]
Regroup terms.
\[\begin{aligned}&\frac{5ethof}{24}+{(\frac{256}{625})}^{-\frac{1}{4}}\\&{(\frac{64}{125})}^{3}\\&\frac{1}{\frac{64}{125}}\end{aligned}\]
(5*e*t*h*o*f)/24+(256/625)^(-1/4);(64/125)^3;1/(64/125)
