$$\frac{ 8 \times - { 1 }^{ 3 } }{ - { 2 }^{ 2 } }$$
$2$
$$\frac{8\left(-1\right)}{-2^{2}}$$
$$\frac{-8}{-2^{2}}$$
$$\frac{-8}{-4}$$
$$2$$
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