Question

$$\frac{ 9 { x }^{ 8 } { y }^{ 3 } }{ { y }^{ 5 } } - \frac{ 7 { x }^{ 8 } { y }^{ 3 } }{ { y }^{ 6 } } - \frac{ 2 { x }^{ 8 } { y }^{ 3 } }{ { y }^{ 5 } }$$

Answer

$$(7*x^8*(y-1))/y^3$$

Solution


Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[9{x}^{8}{y}^{3-5}-\frac{7{x}^{8}{y}^{3}}{{y}^{6}}-\frac{2{x}^{8}{y}^{3}}{{y}^{5}}\]
Simplify  \(3-5\)  to  \(-2\).
\[9{x}^{8}{y}^{-2}-\frac{7{x}^{8}{y}^{3}}{{y}^{6}}-\frac{2{x}^{8}{y}^{3}}{{y}^{5}}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[9{x}^{8}{y}^{-2}-7{x}^{8}{y}^{3-6}-\frac{2{x}^{8}{y}^{3}}{{y}^{5}}\]
Simplify  \(3-6\)  to  \(-3\).
\[9{x}^{8}{y}^{-2}-7{x}^{8}{y}^{-3}-\frac{2{x}^{8}{y}^{3}}{{y}^{5}}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[9{x}^{8}{y}^{-2}-7{x}^{8}{y}^{-3}-2{x}^{8}{y}^{3-5}\]
Simplify  \(3-5\)  to  \(-2\).
\[9{x}^{8}{y}^{-2}-7{x}^{8}{y}^{-3}-2{x}^{8}{y}^{-2}\]
Collect like terms.
\[(\frac{9{x}^{8}}{{y}^{2}}-\frac{2{x}^{8}}{{y}^{2}})-\frac{7{x}^{8}}{{y}^{3}}\]
Simplify.
\[\frac{7{x}^{8}}{{y}^{2}}-\frac{7{x}^{8}}{{y}^{3}}\]
Rewrite the expression with a common denominator.
\[\frac{7{x}^{8}y-7{x}^{8}}{{y}^{3}}\]
Factor out the common term \(7{x}^{8}\).
\[\frac{7{x}^{8}(y-1)}{{y}^{3}}\]