How to solve 9/10 + (- 46)/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9/10 + (- 46)/5 | Equatix

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$$\frac{9}{10}+\frac{(-46)}{5}$$

$-\frac{83}{10}=-8.3$

Fraction $\frac{-46}{5}$ can be rewritten as $-\frac{46}{5}$ by extracting the negative sign.

$$\frac{9}{10}-\frac{46}{5}$$

Least common multiple of $10$ and $5$ is $10$. Convert $\frac{9}{10}$ and $\frac{46}{5}$ to fractions with denominator $10$.

$$\frac{9}{10}-\frac{92}{10}$$

Since $\frac{9}{10}$ and $\frac{92}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-92}{10}$$

Subtract $92$ from $9$ to get $-83$.

$$-\frac{83}{10}$$

$-\frac{83}{10} = -8\frac{3}{10} = -8.3$