How to solve (9)/(15)-(1)/(2)=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (9)/(15)-(1)/(2)= | Equatix

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$$\frac{ 9 }{ 15 } - \frac{ 1 }{ 2 } =$$

$\frac{1}{10}=0.1$

Reduce the fraction $\frac{9}{15}$ to lowest terms by extracting and canceling out $3$.

$$\frac{3}{5}-\frac{1}{2}$$

Least common multiple of $5$ and $2$ is $10$. Convert $\frac{3}{5}$ and $\frac{1}{2}$ to fractions with denominator $10$.

$$\frac{6}{10}-\frac{5}{10}$$

Since $\frac{6}{10}$ and $\frac{5}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-5}{10}$$

Subtract $5$ from $6$ to get $1$.

$$\frac{1}{10}$$

$\frac{1}{2 \cdot 5} = 0.1$