$$[\frac{9}{16}\times\frac{4}{12}]+(\frac{9}{16}\times\frac{-3}{9})$$
$0$
$$\frac{9}{16}\times \frac{1}{3}+\frac{9}{16}\times \frac{-3}{9}$$
$$\frac{9\times 1}{16\times 3}+\frac{9}{16}\times \frac{-3}{9}$$
$$\frac{9}{48}+\frac{9}{16}\times \frac{-3}{9}$$
$$\frac{3}{16}+\frac{9}{16}\times \frac{-3}{9}$$
$$\frac{3}{16}+\frac{9}{16}\left(-\frac{1}{3}\right)$$
$$\frac{3}{16}+\frac{9\left(-1\right)}{16\times 3}$$
$$\frac{3}{16}+\frac{-9}{48}$$
$$\frac{3}{16}-\frac{3}{16}$$
$$0$$
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