Question

$$\frac{9}{3}+\frac{-4}{3}\div\frac{4}{6}; -\frac{-12}{3}=$$

Answer

3-4/3/(2/3);+4

Solution


Simplify  \(\frac{4}{6}\)  to  \(\frac{2}{3}\).
\[\begin{aligned}&\frac{9}{3}-\frac{\frac{4}{3}}{\frac{2}{3}}\\&+\frac{12}{3}\end{aligned}\]
Simplify  \(\frac{9}{3}\)  to  \(3\).
\[\begin{aligned}&3-\frac{\frac{4}{3}}{\frac{2}{3}}\\&+\frac{12}{3}\end{aligned}\]
Simplify  \(\frac{12}{3}\)  to  \(4\).
\[\begin{aligned}&3-\frac{\frac{4}{3}}{\frac{2}{3}}\\&+4\end{aligned}\]