How to solve 9/5 + 7/1 + 14/8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9/5 + 7/1 + 14/8 | Equatix

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Question

$$\frac{9}{5}+\frac{7}{1}+\frac{14}{8}$$

Evaluate

$\frac{211}{20}=10.55$

Solution Steps

Anything divided by one gives itself.

$$\frac{9}{5}+7+\frac{14}{8}$$

Convert $7$ to fraction $\frac{35}{5}$.

$$\frac{9}{5}+\frac{35}{5}+\frac{14}{8}$$

Since $\frac{9}{5}$ and $\frac{35}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{9+35}{5}+\frac{14}{8}$$

Add $9$ and $35$ to get $44$.

$$\frac{44}{5}+\frac{14}{8}$$

Reduce the fraction $\frac{14}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{44}{5}+\frac{7}{4}$$

Least common multiple of $5$ and $4$ is $20$. Convert $\frac{44}{5}$ and $\frac{7}{4}$ to fractions with denominator $20$.

$$\frac{176}{20}+\frac{35}{20}$$

Since $\frac{176}{20}$ and $\frac{35}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{176+35}{20}$$

Add $176$ and $35$ to get $211$.

$$\frac{211}{20}$$

Show Solution

Factor

$\frac{211}{2 ^ {2} \cdot 5} = 10\frac{11}{20} = 10.55$