Question

$$: \frac { 9 } { 5 } \times ( \frac { - 3 } { 11 } ) + \frac { 1 } { 5 } \times ( \frac { - 3 } { 11 } )$$

Answer

$$-(3*(9*Ev*e*a^2*l*u*t+1))/55$$

Solution


Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{Evaluate\times 9\times -3}{5\times 11}+\frac{1}{5}\times \frac{-3}{11}\]
Take out the constants.
\[\frac{(9\times -3)aalutEve}{5\times 11}+\frac{1}{5}\times \frac{-3}{11}\]
Simplify  \(9\times -3\)  to  \(-27\).
\[\frac{-27aalutEve}{5\times 11}+\frac{1}{5}\times \frac{-3}{11}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{-27{a}^{2}lutEve}{5\times 11}+\frac{1}{5}\times \frac{-3}{11}\]
Regroup terms.
\[\frac{-27Eve{a}^{2}lut}{5\times 11}+\frac{1}{5}\times \frac{-3}{11}\]
Simplify  \(5\times 11\)  to  \(55\).
\[\frac{-27Eve{a}^{2}lut}{55}+\frac{1}{5}\times \frac{-3}{11}\]
Move the negative sign to the left.
\[-\frac{27Eve{a}^{2}lut}{55}+\frac{1}{5}\times \frac{-3}{11}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[-\frac{27Eve{a}^{2}lut}{55}+\frac{1\times -3}{5\times 11}\]
Simplify  \(1\times -3\)  to  \(-3\).
\[-\frac{27Eve{a}^{2}lut}{55}+\frac{-3}{5\times 11}\]
Simplify  \(5\times 11\)  to  \(55\).
\[-\frac{27Eve{a}^{2}lut}{55}+\frac{-3}{55}\]
Move the negative sign to the left.
\[-\frac{27Eve{a}^{2}lut}{55}-\frac{3}{55}\]
Join the denominators.
\[\frac{-27Eve{a}^{2}lut-3}{55}\]
Factor out the common term \(3\).
\[\frac{-3(9Eve{a}^{2}lut+1)}{55}\]
Move the negative sign to the left.
\[-\frac{3(9Eve{a}^{2}lut+1)}{55}\]