How to solve 9/6 * 3/2 * 18/7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9/6 * 3/2 * 18/7 | Equatix

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$$\frac{9}{6}\times\frac{3}{2}\times\frac{18}{7}$$

$\frac{81}{14}\approx 5.785714286$

Reduce the fraction $\frac{9}{6}$ to lowest terms by extracting and canceling out $3$.

$$\frac{3}{2}\times \frac{3}{2}\times \frac{18}{7}$$

Multiply $\frac{3}{2}$ times $\frac{3}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 3}{2\times 2}\times \frac{18}{7}$$

Do the multiplications in the fraction $\frac{3\times 3}{2\times 2}$.

$$\frac{9}{4}\times \frac{18}{7}$$

Multiply $\frac{9}{4}$ times $\frac{18}{7}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 18}{4\times 7}$$

Do the multiplications in the fraction $\frac{9\times 18}{4\times 7}$.

$$\frac{162}{28}$$

Reduce the fraction $\frac{162}{28}$ to lowest terms by extracting and canceling out $2$.

$$\frac{81}{14}$$

$\frac{3 ^ {4}}{2 \cdot 7} = 5\frac{11}{14} = 5.785714285714286$