How to solve 9/9 + 2/5 * 4/9 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 9/9 + 2/5 * 4/9 = | Equatix

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$$\frac{9}{9}+\frac{2}{5}\times\frac{4}{9}=$$

$\frac{53}{45}\approx 1.177777778$

Divide $9$ by $9$ to get $1$.

$$1+\frac{2}{5}\times \frac{4}{9}$$

Multiply $\frac{2}{5}$ times $\frac{4}{9}$ by multiplying numerator times numerator and denominator times denominator.

$$1+\frac{2\times 4}{5\times 9}$$

Do the multiplications in the fraction $\frac{2\times 4}{5\times 9}$.

$$1+\frac{8}{45}$$

Convert $1$ to fraction $\frac{45}{45}$.

$$\frac{45}{45}+\frac{8}{45}$$

Since $\frac{45}{45}$ and $\frac{8}{45}$ have the same denominator, add them by adding their numerators.

$$\frac{45+8}{45}$$

Add $45$ and $8$ to get $53$.

$$\frac{53}{45}$$

$\frac{53}{3 ^ {2} \cdot 5} = 1\frac{8}{45} = 1.1777777777777778$