$$\frac{9}{d+2}\cdot\frac{2\ d-16}{d-8}=$$
$\frac{18}{d+2}$
$$\frac{9}{d+2}\times \frac{2\left(d-8\right)}{d-8}$$
$$\frac{9}{d+2}\times 2$$
$$\frac{9\times 2}{d+2}$$
$$\frac{18}{d+2}$$
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