$$\frac{91}{41}(\frac{-2}{3})+(\frac{4}{3})\frac{91}{41}+(\frac{-2}{3})\frac{91}{41}$$
$0$
$$\frac{91}{41}\left(-\frac{2}{3}\right)+\frac{4}{3}\times \frac{91}{41}+\frac{-2}{3}\times \frac{91}{41}$$
$$\frac{91\left(-2\right)}{41\times 3}+\frac{4}{3}\times \frac{91}{41}+\frac{-2}{3}\times \frac{91}{41}$$
$$\frac{-182}{123}+\frac{4}{3}\times \frac{91}{41}+\frac{-2}{3}\times \frac{91}{41}$$
$$-\frac{182}{123}+\frac{4}{3}\times \frac{91}{41}+\frac{-2}{3}\times \frac{91}{41}$$
$$-\frac{182}{123}+\frac{4\times 91}{3\times 41}+\frac{-2}{3}\times \frac{91}{41}$$
$$-\frac{182}{123}+\frac{364}{123}+\frac{-2}{3}\times \frac{91}{41}$$
$$\frac{-182+364}{123}+\frac{-2}{3}\times \frac{91}{41}$$
$$\frac{182}{123}+\frac{-2}{3}\times \frac{91}{41}$$
$$\frac{182}{123}-\frac{2}{3}\times \frac{91}{41}$$
$$\frac{182}{123}+\frac{-2\times 91}{3\times 41}$$
$$\frac{182}{123}+\frac{-182}{123}$$
$$\frac{182}{123}-\frac{182}{123}$$
$$0$$
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