$$\frac{96x-4x^{2}-1.2x^{3}}{16x-1.2x^{3}}dx$$
$-\frac{dx\left(240-10x-3x^{2}\right)}{3x^{2}-40}$
$\frac{3dx^{3}+10dx^{2}-240dx}{3x^{2}-40}$
