Question

$$\frac { 9x } { 7-4z } =15$$

Answer

x=(5*(7-4*z))/3

Solution


Remove parentheses.
\[\times \frac{9x}{7-4z}=15\]
Simplify  \(\times \frac{9x}{7-4z}\)  to  \(\frac{9x}{7-4z}\).
\[\frac{9x}{7-4z}=15\]
Multiply both sides by \(7-4z\).
\[9x=15(7-4z)\]
Divide both sides by \(9\).
\[x=\frac{15(7-4z)}{9}\]
Simplify  \(\frac{15(7-4z)}{9}\)  to  \(\frac{5(7-4z)}{3}\).
\[x=\frac{5(7-4z)}{3}\]