Solve ()((9x)/(7-6z))=15 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac { 9x } { 7-6z } =15$$

Solve for x

$x=\frac{35}{3}-10z$
$z\neq \frac{7}{6}$

Steps for Solving Linear Equation

Multiply both sides of the equation by $-6z+7$.

$$9x=15\left(-6z+7\right)$$

Use the distributive property to multiply $15$ by $-6z+7$.

$$9x=-90z+105$$

The equation is in standard form.

$$9x=105-90z$$

Divide both sides by $9$.

$$\frac{9x}{9}=\frac{105-90z}{9}$$

Dividing by $9$ undoes the multiplication by $9$.

$$x=\frac{105-90z}{9}$$

Divide $-90z+105$ by $9$.

$$x=\frac{35}{3}-10z$$

Solve for z

$z=-\frac{x}{10}+\frac{7}{6}$
$x\neq 0$

Steps for Solving Linear Equation

Variable $z$ cannot be equal to $\frac{7}{6}$ since division by zero is not defined. Multiply both sides of the equation by $-6z+7$.

$$9x=15\left(-6z+7\right)$$

Use the distributive property to multiply $15$ by $-6z+7$.

$$9x=-90z+105$$

Swap sides so that all variable terms are on the left hand side.

$$-90z+105=9x$$

Subtract $105$ from both sides.

$$-90z=9x-105$$

Divide both sides by $-90$.

$$\frac{-90z}{-90}=\frac{9x-105}{-90}$$

Dividing by $-90$ undoes the multiplication by $-90$.

$$z=\frac{9x-105}{-90}$$

Divide $9x-105$ by $-90$.

$$z=-\frac{x}{10}+\frac{7}{6}$$

Variable $z$ cannot be equal to $\frac{7}{6}$.

$$z=-\frac{x}{10}+\frac{7}{6}\text{, }z\neq \frac{7}{6}$$