$$\frac{9x^{2}-(x^{2}-4)^{2}}{4+3x-x^{2}}$$
$\left(x-1\right)\left(x+4\right)$
$$\frac{\left(x-4\right)\left(x-1\right)\left(-x-1\right)\left(x+4\right)}{\left(x-4\right)\left(-x-1\right)}$$
$$\left(x-1\right)\left(x+4\right)$$
$$x^{2}+3x-4$$
Show Solution
Hide Solution
$x^{2}+3x-4$
