$$\frac{9y}{g-5}\div\frac{9y}{7y-35}$$
$\frac{7\left(y-5\right)}{g-5}$
$$\frac{9y\left(7y-35\right)}{\left(g-5\right)\times 9y}$$
$$\frac{7y-35}{g-5}$$
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$\frac{7}{g-5}$