$$\frac { a } { 2 } + \frac { a } { 3 } + \frac { a } { 4 }$$
$\frac{13a}{12}$
$$\frac{5}{6}a+\frac{a}{4}$$
$$\frac{13}{12}a$$
Show Solution
Hide Solution
$\frac{13}{12} = 1\frac{1}{12} = 1.0833333333333333$
$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{5}{6}a+\frac{a}{4})$$
$$\frac{\mathrm{d}}{\mathrm{d}a}(\frac{13}{12}a)$$
$$\frac{13}{12}a^{1-1}$$
$$\frac{13}{12}a^{0}$$
$$\frac{13}{12}\times 1$$
$$\frac{13}{12}$$
