Question

$$\frac{a-8}{b^{9}}:\frac{(a-8)^{3}}{b^{9}}$$

Answer

$$1/(a-8)^2$$

Solution


Invert and multiply.
\[\frac{a-8}{{b}^{9}}\times \frac{{b}^{9}}{{(a-8)}^{3}}\]
Cancel \({b}^{9}\).
\[(a-8)\times \frac{1}{{(a-8)}^{3}}\]
Simplify.
\[\frac{a-8}{{(a-8)}^{3}}\]
Simplify.
\[\frac{1}{{(a-8)}^{2}}\]