$$\frac{ a+1 }{ 3 } + \frac{ 2a-3 }{ 5 } =10$$
$a=14$
$$5\left(a+1\right)+3\left(2a-3\right)=150$$
$$5a+5+3\left(2a-3\right)=150$$
$$5a+5+6a-9=150$$
$$11a+5-9=150$$
$$11a-4=150$$
$$11a=150+4$$
$$11a=154$$
$$a=\frac{154}{11}$$
$$a=14$$
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