$$\frac { a ^ { 2 } b } { 4 a b } + \frac { b ^ { 2 } a } { 4 a b } + \frac { 3 } { 4 }$$
$\frac{a+b+3}{4}$
$$\frac{a}{4}+\frac{b^{2}a}{4ab}+\frac{3}{4}$$
$$\frac{a}{4}+\frac{b}{4}+\frac{3}{4}$$
$$\frac{a+b}{4}+\frac{3}{4}$$
$$\frac{a+b+3}{4}$$
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