Divide $\frac{a^{2}-b^{2}}{3x^{3}-3b^{3}}$ by $\frac{a-b}{x^{2}+bx+b^{2}}$ by multiplying $\frac{a^{2}-b^{2}}{3x^{3}-3b^{3}}$ by the reciprocal of $\frac{a-b}{x^{2}+bx+b^{2}}$.
Divide $\frac{a^{2}-b^{2}}{3x^{3}-3b^{3}}$ by $\frac{a-b}{x^{2}+bx+b^{2}}$ by multiplying $\frac{a^{2}-b^{2}}{3x^{3}-3b^{3}}$ by the reciprocal of $\frac{a-b}{x^{2}+bx+b^{2}}$.
