$$\frac { A ^ { 4 } } { 3 }$$
$\frac{4A^{3}}{3}$
$$4\times \frac{1}{3}A^{4-1}$$
$$\frac{4}{3}A^{4-1}$$
$$\frac{4}{3}A^{3}$$
Show Solution
Hide Solution
$\frac{A^{4}}{3}$
