Question

$$\frac{\boxed{4t+1}}{(t^{2}+2)^{2}}=$$

Answer

$$4*boxe*d*t+(t^2+2)^2$$

Solution


Regroup terms.
\[4boxedt+1\times {({t}^{2}+2)}^{2}\]
Simplify  \(1\times {({t}^{2}+2)}^{2}\)  to  \({({t}^{2}+2)}^{2}\).
\[4boxedt+{({t}^{2}+2)}^{2}\]