Solve 4 (2c)/9 - (c - 1)/6 = (c + 3)/12 olve the followin 10 24 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac { c } { 9 } - \frac { c - 1 } { 6 } = \frac { c + 3 } { 12 }$$

Solve for c

$c=-\frac{3}{5}=-0.6$

Steps for Solving Linear Equation

Multiply both sides of the equation by $36$, the least common multiple of $9,6,12$.

$$4c-6\left(c-1\right)=3\left(c+3\right)$$

Use the distributive property to multiply $-6$ by $c-1$.

$$4c-6c+6=3\left(c+3\right)$$

Combine $4c$ and $-6c$ to get $-2c$.

$$-2c+6=3\left(c+3\right)$$

Use the distributive property to multiply $3$ by $c+3$.

$$-2c+6=3c+9$$

Subtract $3c$ from both sides.

$$-2c+6-3c=9$$

Combine $-2c$ and $-3c$ to get $-5c$.

$$-5c+6=9$$

Subtract $6$ from both sides.

$$-5c=9-6$$

Subtract $6$ from $9$ to get $3$.

$$-5c=3$$

Divide both sides by $-5$.

$$c=\frac{3}{-5}$$

Fraction $\frac{3}{-5}$ can be rewritten as $-\frac{3}{5}$ by extracting the negative sign.

$$c=-\frac{3}{5}$$