Question

$$\frac{ { 3 }^{ 2 } }{ \frac{ { 4 }^{ 2 } }{ \frac{ { 9 }^{ 2 } }{ \times 6 } } } = { 6 }^{ 2 } \times { 359 }^{ 2 }$$

Answer

[No Solution]

Solution


Simplify  \({9}^{2}\)  to  \(81\).
\[\frac{{3}^{2}}{\frac{{4}^{2}}{\frac{81}{\times 6}}}={6}^{2}\times {359}^{2}\]
Use this rule: \(\frac{a}{b} \times c=\frac{ac}{b}\).
\[\frac{{3}^{2}}{\frac{{4}^{2}}{81\times 6}}={6}^{2}\times {359}^{2}\]
Simplify  \(81\times 6\)  to  \(486\).
\[\frac{{3}^{2}}{\frac{{4}^{2}}{486}}={6}^{2}\times {359}^{2}\]
Simplify  \({4}^{2}\)  to  \(16\).
\[\frac{{3}^{2}}{\frac{16}{486}}={6}^{2}\times {359}^{2}\]
Simplify  \(\frac{16}{486}\)  to  \(\frac{8}{243}\).
\[\frac{{3}^{2}}{\frac{8}{243}}={6}^{2}\times {359}^{2}\]
Simplify  \({3}^{2}\)  to  \(9\).
\[\frac{9}{\frac{8}{243}}={6}^{2}\times {359}^{2}\]
Simplify  \({6}^{2}\)  to  \(36\).
\[\frac{9}{\frac{8}{243}}=36\times {359}^{2}\]
Simplify  \({359}^{2}\)  to  \(128881\).
\[\frac{9}{\frac{8}{243}}=36\times 128881\]
Invert and multiply.
\[9\times \frac{243}{8}=36\times 128881\]
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[\frac{9\times 243}{8}=36\times 128881\]
Simplify  \(9\times 243\)  to  \(2187\).
\[\frac{2187}{8}=36\times 128881\]
Simplify  \(36\times 128881\)  to  \(4639716\).
\[\frac{2187}{8}=4639716\]
Since \(\frac{2187}{8}=4639716\) is false, there is no solution.
No Solution