$$\frac{ { x }^{ 3 } }{ 3y } \times \frac{ 5x }{ { y }^{ 3 } } \div \frac{ 10 { x }^{ 4 } }{ 9 { y }^{ 4 } }$$
$\frac{3}{2}=1.5$
$$\frac{\frac{x^{3}\times 5x}{3yy^{3}}}{\frac{10x^{4}}{9y^{4}}}$$
$$\frac{x^{3}\times 5x\times 9y^{4}}{3yy^{3}\times 10x^{4}}$$
$$\frac{3}{2}$$
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$\frac{3}{2} = 1\frac{1}{2} = 1.5$
