Question

$$\frac{}{8-}\omega_{S}=\omega\epsilon$$

Answer

o=8/(m*e*g*(aepsilon+aS))

Solution


Add \(omegaS\) to both sides.
\[8=omegaepsilon+omegaS\]
Factor out the common term \(omeg\).
\[8=omeg(aepsilon+aS)\]
Divide both sides by \(m\).
\[\frac{8}{m}=oeg(aepsilon+aS)\]
Divide both sides by \(e\).
\[\frac{\frac{8}{m}}{e}=og(aepsilon+aS)\]
Simplify  \(\frac{\frac{8}{m}}{e}\)  to  \(\frac{8}{me}\).
\[\frac{8}{me}=og(aepsilon+aS)\]
Divide both sides by \(g\).
\[\frac{\frac{8}{me}}{g}=o(aepsilon+aS)\]
Simplify  \(\frac{\frac{8}{me}}{g}\)  to  \(\frac{8}{meg}\).
\[\frac{8}{meg}=o(aepsilon+aS)\]
Divide both sides by \(aepsilon+aS\).
\[\frac{\frac{8}{meg}}{aepsilon+aS}=o\]
Simplify  \(\frac{\frac{8}{meg}}{aepsilon+aS}\)  to  \(\frac{8}{meg(aepsilon+aS)}\).
\[\frac{8}{meg(aepsilon+aS)}=o\]
Switch sides.
\[o=\frac{8}{meg(aepsilon+aS)}\]