Question

$$\frac { d p } { d } \theta + 3 p = 2$$

Solve for d

$d\neq 0$
$p=\frac{2}{\theta +3}\text{ and }\theta \neq -3$

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Solve for p

$p=\frac{2}{\theta +3}$
$\theta \neq -3\text{ and }d\neq 0$

Show Solution