Question

$$\frac { d y } { d x } y = x ^ { x }$$

Answer

$$n=x^(x-1)/(Fi*IM*d*y^2*f)$$

Solution


Cancel \(d\).
\[Findxy\imath fy={x}^{x}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[Findx{y}^{2}\imath f={x}^{x}\]
Regroup terms.
\[Fi\imath ndx{y}^{2}f={x}^{x}\]
Divide both sides by \(Fi\).
\[\imath ndx{y}^{2}f=\frac{{x}^{x}}{Fi}\]
Divide both sides by \(\imath \).
\[ndx{y}^{2}f=\frac{\frac{{x}^{x}}{Fi}}{\imath }\]
Simplify  \(\frac{\frac{{x}^{x}}{Fi}}{\imath }\)  to  \(\frac{{x}^{x}}{Fi\imath }\).
\[ndx{y}^{2}f=\frac{{x}^{x}}{Fi\imath }\]
Divide both sides by \(d\).
\[nx{y}^{2}f=\frac{\frac{{x}^{x}}{Fi\imath }}{d}\]
Simplify  \(\frac{\frac{{x}^{x}}{Fi\imath }}{d}\)  to  \(\frac{{x}^{x}}{Fi\imath d}\).
\[nx{y}^{2}f=\frac{{x}^{x}}{Fi\imath d}\]
Divide both sides by \(x\).
\[n{y}^{2}f=\frac{\frac{{x}^{x}}{Fi\imath d}}{x}\]
Simplify  \(\frac{\frac{{x}^{x}}{Fi\imath d}}{x}\)  to  \(\frac{{x}^{x}}{Fi\imath dx}\).
\[n{y}^{2}f=\frac{{x}^{x}}{Fi\imath dx}\]
Simplify  \(\frac{{x}^{x}}{Fi\imath dx}\)  to  \(\frac{{x}^{x-1}}{Fi\imath d}\).
\[n{y}^{2}f=\frac{{x}^{x-1}}{Fi\imath d}\]
Divide both sides by \({y}^{2}\).
\[nf=\frac{\frac{{x}^{x-1}}{Fi\imath d}}{{y}^{2}}\]
Simplify  \(\frac{\frac{{x}^{x-1}}{Fi\imath d}}{{y}^{2}}\)  to  \(\frac{{x}^{x-1}}{Fi\imath d{y}^{2}}\).
\[nf=\frac{{x}^{x-1}}{Fi\imath d{y}^{2}}\]
Divide both sides by \(f\).
\[n=\frac{\frac{{x}^{x-1}}{Fi\imath d{y}^{2}}}{f}\]
Simplify  \(\frac{\frac{{x}^{x-1}}{Fi\imath d{y}^{2}}}{f}\)  to  \(\frac{{x}^{x-1}}{Fi\imath d{y}^{2}f}\).
\[n=\frac{{x}^{x-1}}{Fi\imath d{y}^{2}f}\]