$$\frac{dy}{10}=(3-x^{2})(x^{2}-x+1)$$
$\left\{\begin{matrix}d=-\frac{10\left(x^{2}-3\right)\left(x^{2}-x+1\right)}{y}\text{, }&y\neq 0\\d\in \mathrm{R}\text{, }&y=0\text{ and }|x|=\sqrt{3}\end{matrix}\right.$
$$dy=10\left(3-x^{2}\right)\left(x^{2}-x+1\right)$$
$$dy=\left(30-10x^{2}\right)\left(x^{2}-x+1\right)$$
$$dy=20x^{2}-30x+30-10x^{4}+10x^{3}$$
$$yd=30-30x+20x^{2}+10x^{3}-10x^{4}$$
$$\frac{yd}{y}=\frac{10\left(-x^{2}+x-1\right)\left(x^{2}-3\right)}{y}$$
$$d=\frac{10\left(-x^{2}+x-1\right)\left(x^{2}-3\right)}{y}$$
Show Solution
Hide Solution
