How to solve 2 5x + 1- 3 c y

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2 5x + 1- 3 c y | Equatix

Question

$$\frac{\frac{2}{5x}+}{1-\frac{3}{c_{y}}}$$

Evaluate

$\frac{4y\left(5x+1\right)}{x\left(10y-3\right)}$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply $2$ times $\frac{5x}{5x}$.

$$\frac{\frac{2}{5x}+\frac{2\times 5x}{5x}}{1-\frac{3}{10y}}$$

Since $\frac{2}{5x}$ and $\frac{2\times 5x}{5x}$ have the same denominator, add them by adding their numerators.

$$\frac{\frac{2+2\times 5x}{5x}}{1-\frac{3}{10y}}$$

Do the multiplications in $2+2\times 5x$.

$$\frac{\frac{2+10x}{5x}}{1-\frac{3}{10y}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply $1$ times $\frac{10y}{10y}$.

$$\frac{\frac{2+10x}{5x}}{\frac{10y}{10y}-\frac{3}{10y}}$$

Since $\frac{10y}{10y}$ and $\frac{3}{10y}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{2+10x}{5x}}{\frac{10y-3}{10y}}$$

Divide $\frac{2+10x}{5x}$ by $\frac{10y-3}{10y}$ by multiplying $\frac{2+10x}{5x}$ by the reciprocal of $\frac{10y-3}{10y}$.

$$\frac{\left(2+10x\right)\times 10y}{5x\left(10y-3\right)}$$

Cancel out $5$ in both numerator and denominator.

$$\frac{2y\left(10x+2\right)}{x\left(10y-3\right)}$$

Use the distributive property to multiply $2y$ by $10x+2$.

$$\frac{20yx+4y}{x\left(10y-3\right)}$$

Use the distributive property to multiply $x$ by $10y-3$.

$$\frac{20yx+4y}{10xy-3x}$$

Show Solution

Expand

$\frac{4\left(5xy+y\right)}{x\left(10y-3\right)}$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply $2$ times $\frac{5x}{5x}$.

$$\frac{\frac{2}{5x}+\frac{2\times 5x}{5x}}{1-\frac{3}{10y}}$$

Since $\frac{2}{5x}$ and $\frac{2\times 5x}{5x}$ have the same denominator, add them by adding their numerators.

$$\frac{\frac{2+2\times 5x}{5x}}{1-\frac{3}{10y}}$$

Do the multiplications in $2+2\times 5x$.

$$\frac{\frac{2+10x}{5x}}{1-\frac{3}{10y}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply $1$ times $\frac{10y}{10y}$.

$$\frac{\frac{2+10x}{5x}}{\frac{10y}{10y}-\frac{3}{10y}}$$

Since $\frac{10y}{10y}$ and $\frac{3}{10y}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{2+10x}{5x}}{\frac{10y-3}{10y}}$$

Divide $\frac{2+10x}{5x}$ by $\frac{10y-3}{10y}$ by multiplying $\frac{2+10x}{5x}$ by the reciprocal of $\frac{10y-3}{10y}$.

$$\frac{\left(2+10x\right)\times 10y}{5x\left(10y-3\right)}$$

Cancel out $5$ in both numerator and denominator.

$$\frac{2y\left(10x+2\right)}{x\left(10y-3\right)}$$

Use the distributive property to multiply $2y$ by $10x+2$.

$$\frac{20yx+4y}{x\left(10y-3\right)}$$

Use the distributive property to multiply $x$ by $10y-3$.

$$\frac{20yx+4y}{10xy-3x}$$

Show Solution

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